Manipulate formulas

Algebraic Manipulation. The key to solving simple algebraic equations containing a single unknown (e.g. x + 6 = 10) is to realize that the equation is an equality. As long as you do the same mathematical operation (e.g. add a constant, subtract a constant, multiply by a constant, and divide by a constant) to both sides of the equation, the equality is still an equality. Algebraic manipulation involves rearranging and substituting for variables to obtain an algebraic expression in a desired form. During this rearrangement, the value of the expression does not change. During this rearrangement, the value of the expression does not change.

Math Skills Review Algebraic Manipulation. To solve for x, you need to add 6 to both sides of the equation and then divide both sides by 2. To isolate x, you need to 1 multiply through by 6, 2 subtract 2 from both sides, and 3 divide both sides by 5. To solve for x this time, you need to 1 multiply both sides of the equation by 4 and 3 to cancel out the denominator in line 2, 2 use the distributive law, 3 by adding and subtracting, move the x terms to one side, and the non-x terms to the other side in line 5, 4 use the associative law to simplify to get line 7, and 5 divide both sides by 2.

This process is called "cross-multiplying. When this is done, the very same line 3 results. The rest of the problem is done identically. This problem could be very complicated and become a what can you do for baby cradle cap equation.

However, because it has a perfect square on both sides, if you simply take eqiations square root of both sides of the equality, you are left in line 3 with a straightforward algebra problem as you solve algebbraic the positive root, which I did here. In Chemistry, when we use this technique to solve equilibrium problems, only one of the roots is meaningful. Dimensional Analysis. Significant Figures.

Manipulation of Exponents. Scientific Notation. The Quadratic Equation.

Manipulating expressions with unknown variables

Math Algebra 2 Modeling Manipulating formulas. Manipulating formulas. Manipulating formulas: perimeter. Manipulating formulas: area. Manipulating formulas: temperature. Practice: Manipulate formulas. This is the currently selected item. Next lesson. Modeling with two variables. Aug 04, · Practice this lesson yourself on odishahaalchaal.com right now:odishahaalchaal.com Apr 10, · Hello, I've been studying Linear Algebra, and have been working with Vectors. I'm pretty familiar with many of the vector concepts, Normalization, Vector addition and subtraction, Dot Products and the like. The question I have is under what subject does the "Algebraic Manipulation" of vector.

Forums New posts Search forums. What's new New posts Latest activity. Log in Register. Search titles only. Search Advanced search…. New posts. Search forums. Log in. For a better experience, please enable JavaScript in your browser before proceeding. Thread starter programmerBlack Start date Apr 10, Joined Aug 15, Messages Hello, I've been studying Linear Algebra, and have been working with Vectors. I'm pretty familiar with many of the vector concepts, Normalization, Vector addition and subtraction, Dot Products and the like.

The question I have is under what subject does the "Algebraic Manipulation" of vector equations fall under? I cannot find any resources on the subject. I find myself having a hard time manipulating equations that feature operations like the Dot Product. What I"m looking for is, what are the rules that define the "What you do to one side, you should do to the other side" concepts when vectors are involved in an Algebraic equation?

If I was given then vector a , and theta , how would I go about solving for b? This obviously would require some algebraic manipulations. And at some point I would be required to divide both sides by the vector a. Which immediately doesn't make sense to me. And there lies my problem. Where can I find out how to manipulate this equation "algebraically", and still be able to work with vectors as inputs.

Thanks in advance for any responses. Much appreciated. Joined Jan 16, Messages 2, Subhotosh Khan Super Moderator Staff member. Joined Jun 18, Messages 24, Joined Jan 29, Messages 10, I've been studying Linear Algebra, and have been working with Vectors.

Subhotosh Khan said:. The part a. By the way, dividing by vector is not defined however you can fin "product" of two vectors in different ways. Just make a drawing - what vectors are normal to the x axis? Well, any vector with 0 x coordinate. Quite literally there need to be only 1 unknown. I'm now assuming when I'm working with these kinds of equations, I should expand out the vectors to component form? I'm basically looking for a vector that when dotted with b, there 90 degrees in between them - algebraically.

Peterson Elite Member. Joined Nov 12, Messages 11, Peterson said:. The way you are asking this is extremely confusing, due to notation and other issues. The two sides not only are equal in some particular case you are solving for, but mean the same thing. The equation is true for any two vectors; but theta is defined as the angle between the two vectors, and is not independent of them.

It appears that you are saying that you would be given a vector b in three-dimensional space and an angle theta, and want to find a vector a such that the angle between them is theta.

Do you see, just by visualizing it, that there will be infinitely many such vectors a? They will form a cone around b , so to speak. In your specific example, any vector orthogonal perpendicular to b will work, and those will form a plane.

One way to find a vector like that would be to choose any other vector and take the cross product with b. If you want to pose a solvable problem for us to help you with, you will need to give more information -- say, the angles between vector a and two given vectors b and c. Even then, any vector of any length in one of two different directions would be a solution.

Perhaps you need to give us a specific scenario that you are trying to program, rather than trying to make up a simplified example. I'm looking for, the opposite of Multiplication is Divison. The opposite of Addition is Subtraction. So does the Dot product have an opposite operation? What about other Linear Algebra operations?

Adding and subtracting vectors seems to work and are inverses of each other. This is less about a specific Math Problem I was working on, and more about the operations rules that can be taken on equations involving vectors.

Hmmm, thanks Dr. Peterson and others. I will spend some time trying to think of the proper question to ask. Originally I was just trying to find some resources that give the rules for dealing with vectors "when used in equations". Similar to the algebra rules defined here: Algebra Cheat Sheet. Not necessarily the answer to a specific question. Ahh Dr. Peterson and Pka. Thank you very much for your time. I understand now.

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